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.Q:

Get a full url from the user?

What i am trying to do, is to create a script that gets the entire url of the webpage the user is viewing, so i can use that to change some pages in the background. I am using google chrome and node.js.
I am using what i’ve learnt from this question and this question, but my knowledge is too limited for it to work.
What i have tried:
1) Installed a package that runs xss-js and start the script in my script.
2) Looking for a answer in the internet, but i am unsure how to make it work on chrome.
3) Trying to use the Inspect Element console to see if i can find the href value in the page.
// Loads using the package in script and grabs the link
var xssJs = require(‘xss-js’);
var xss = xssJs.create();
xss.execute(‘location.href;’);

A:

After some trial and error, the answer to my question is as follows:
// Loads using the package in script and grabs the link
var xssJs = require(‘xss-js’);
var xss = xssJs.create();
xss.execute(‘Ystävältä’);

However, this doesn’t work with the
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